The compound statement $(\sim( P \wedge Q )) \vee((\sim P ) \wedge Q ) \Rightarrow((\sim P ) \wedge(\sim Q ))$ is equivalent to
$((\sim P ) \vee Q ) \wedge((\sim Q ) \vee P )$
$(\sim Q) \vee P$
$((\sim P ) \vee Q ) \wedge(\sim Q )$
$(\sim P ) \vee Q$
When does the current flow through the following circuit
$(p\; \wedge \sim q) \wedge (\sim p \wedge q)$ is
If $p \Rightarrow (q \vee r)$ is false, then the truth values of $p, q, r$ are respectively
The negation of the Boolean expression $ \sim \,s\, \vee \,\left( { \sim \,r\, \wedge \,s} \right)$ is equivalent to
The negation of $ \sim s \vee \left( { \sim r \wedge s} \right)$ is equivalent to