મિશ્ર વિધાન (∼(P wedge Q)) vee((∼ P) wedge Q) ⇒((∼ P) wedge(∼ Q)) એ

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Mathematical Reasoning

hard

મિશ્ર વિધાન $(\sim(P \wedge Q)) \vee((\sim P) \wedge Q) \Rightarrow((\sim P) \wedge(\sim Q))$ એ $...........$ ને સમકક્ષ છે.

$((\sim P ) \vee Q ) \wedge((\sim Q ) \vee P )$

$(\sim Q) \vee P$

$((\sim P ) \vee Q ) \wedge(\sim Q )$

$(\sim P ) \vee Q$

(JEE MAIN-2023)

Solution

Let $\quad r =(\sim( P \wedge Q )) \vee((\sim P ) \wedge Q ) ; \quad s =$ $((\sim P ) \wedge(\sim Q ))$

Option (A) : $((\sim P ) \vee Q ) \wedge((\sim Q ) \vee P )$ is equivalent to (not of only $P) \wedge($ not of only $Q$) $=($ Both $P , Q )$ and (neither $P$ nor $Q )$

Standard 11

Mathematics

$\pi$

normal

નીચેનું વિધાન: $\left( {p \to q} \right) \to $ $[(\sim p\rightarrow q) \rightarrow q ]$ એ . . . . .

hard

(JEE MAIN-2017)

$p \wedge( q \wedge \sim( p \wedge q ))$નું નિષેધ $…………$ છે.

medium

(JEE MAIN-2023)

વિધાન $ \sim \left( {p \leftrightarrow \sim q} \right)$

normal

$(p\rightarrow q) \leftrightarrow (q \vee ~ p)$ એ

normal

મિશ્ર વિધાન $(\sim(P \wedge Q)) \vee((\sim P) \wedge Q) \Rightarrow((\sim P) \wedge(\sim Q))$ એ $...........$ ને સમકક્ષ છે.

Solution

Similar Questions

$\pi$

નીચેનું વિધાન: $\left( {p \to q} \right) \to $ $[(\sim p\rightarrow q) \rightarrow q ]$ એ . . . . .

$p \wedge( q \wedge \sim( p \wedge q ))$નું નિષેધ $…………$ છે.

વિધાન $ \sim \left( {p \leftrightarrow \sim q} \right)$

$(p\rightarrow q) \leftrightarrow (q \vee ~ p)$ એ

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