Dual of $(x \vee y) \wedge (x \vee 1) = x \vee (x \wedge y) \vee y$ is
Dual of $(x \vee y) \wedge (x \vee 1) = x \vee (x \wedge y) \vee y$ is
- A
$(x \wedge y) \vee (x \wedge 0) = x \wedge (x \vee y) \wedge y$
- B
$(x \vee y) \vee (x \wedge 1) = x \wedge (x \vee y) \wedge y$
- C
$(x \wedge y) \wedge (x \wedge 0) = x \wedge (x \vee y) \wedge y$
- D
None of these
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