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13.Nuclei
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The count rate of a Geiger- Muller counter for the radiation of a radioactive material of half life of $30\, minutes$ decreases to $5\,{s^{ - 1}}$ after $2\, hours.$ The initial count rate was..........${s^{ - 1}}$
A
$25$
B
$80$
C
$625$
D
$20$
(AIPMT-1995)
Solution
(b) $A = {A_0}{\left( {\frac{1}{2}} \right)^{t/{T_{1/2}}}}$
$⇒$$5 = {A_0}{\left( {\frac{1}{2}} \right)^{\frac{{2 \times 60}}{{30}}}} = \frac{{{A_0}}}{{16}}$
$⇒$ ${A_0} = 80\,se{c^{ – 1}}$
Standard 12
Physics
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