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1.Units, Dimensions and Measurement
medium
$MKS$ पद्धति में विद्युत वाहक बल की विमा है
A$M{L^{ - 1}}{T^{ - 2}}{Q^{ - 2}}$
B$M{L^2}{T^{ - 2}}{Q^{ - 2}}$
C$ML{T^{ - 2}}{Q^{ - 1}}$
D$M{L^2}{T^{ - 2}}{Q^{ - 1}}$
Solution
(d) $e = L\frac{{di}}{{dt}} \Rightarrow [e] = [M{L^2}{T^{ – 2}}{A^{ – 2}}]\,\left[ {\frac{A}{T}} \right]$
$[e] = \left[ {\frac{{M{L^2}{T^{ – 2}}}}{{AT}}} \right] = [M{L^2}{T^{ – 2}}{Q^{ – 1}}]$
$[e] = \left[ {\frac{{M{L^2}{T^{ – 2}}}}{{AT}}} \right] = [M{L^2}{T^{ – 2}}{Q^{ – 1}}]$
Standard 11
Physics
