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1.Units, Dimensions and Measurement
hard
કોણીય વેગમાન, ગુપ્ત ઉષ્મા અને કેપેસીટન્સ ના પરિમાણ અનુક્રમે શું થાય?
A$ML^2T^1A^2 ,\, L^2T^{-2},\, M^{-1}L^{-2}T^2$
B$ML^2T^{-2} ,\, L^2T^2,\, M^{-1}L^{-2}T^4A^2$
C$ML^2T^{-1} ,\, L^2T^{-2},\, ML^2TA^2$
D$ML^2T^{-1} ,\, L^2T^{-2},\, M^{-1}L^{-2}T^4A^2$
(JEE MAIN-2013)
Solution
$\begin{array}{l}
Angular\,momentum\, = m \times v\, \times r\\
= M{L^2}{T^{ – 1}}\\
Latent\,heat\,L = \frac{Q}{m} = \frac{{M{L^2}{T^{ – 2}}}}{M} = {L^2}{T^{ – 2}}\\
{\rm{Capacitance}}\,C = \frac{{Ch\arg e}}{{p.d}} = {M^{ – 1}}{L^{ – 2}}{T^4}{A^2}
\end{array}$
Angular\,momentum\, = m \times v\, \times r\\
= M{L^2}{T^{ – 1}}\\
Latent\,heat\,L = \frac{Q}{m} = \frac{{M{L^2}{T^{ – 2}}}}{M} = {L^2}{T^{ – 2}}\\
{\rm{Capacitance}}\,C = \frac{{Ch\arg e}}{{p.d}} = {M^{ – 1}}{L^{ – 2}}{T^4}{A^2}
\end{array}$
Standard 11
Physics
