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1.Units, Dimensions and Measurement
medium
The dimensions of shear modulus are
A$ML{T^{ - 1}}$
B$M{L^2}{T^{ - 2}}$
C$M{L^{ - 1}}{T^{ - 2}}$
D$ML{T^{ - 2}}$
Solution
(c) Shear modulus = $\frac{{{\rm{Shearing\, stress}}}}{{{\rm{Shearing\, strain }}}}$ $ = \frac{F}{{A\theta }} $ $= [M{L^{ – 1}}{T^{ – 2}}]$
Standard 11
Physics