The dimensions of the product $\mu_{0} \varepsilon_{0}$ are related to those of velocity as
$(velocity)^2$
$velocity$
$1/velocity$
$1/(velocity)^2$
The fundamental unit which has the same power in the dimension formula of surface tension and viscosity is
If the buoyant force $F$ acting on an object depends on its volume $V$ immersed in a liquid, the density $\rho$ of the liquid and the acceleration due to gravity $g$. The correct expression for $F$ can be
If velocity$(V)$, force$(F)$ and time$(T)$ are chosen as fundamental quantities then dimensions of energy are
If time $(t)$, velocity $(u)$, and angular momentum $(I)$ are taken as the fundamental units. Then the dimension of mass $({m})$ in terms of ${t}, {u}$ and ${I}$ is
The dimensions of permittivity ${\varepsilon _0}$ are