Pressure gradient has the same dimension as t | vedclass

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Question

(d) Velocity gradient $ = \frac{v}{x} = \frac{{[L{T^{ - 1}}]}}{{[L]}} = [{T^{ - 1}}]$
Potential gradient$ = \frac{V}{x} = \frac{{[M{L^2}{T^{ - 3}}{A^

Vedclass · Accepted Answer

None of these

Vedclass · Answer

(d) Velocity gradient $ = \frac{v}{x} = \frac{{[L{T^{ - 1}}]}}{{[L]}} = [{T^{ - 1}}]$
Potential gradient$ = \frac{V}{x} = \frac{{[M{L^2}{T^{ - 3}}{A^{ - 1}}]}}{{[L]}}$$ = [ML{T^{ - 3}}{A^{ - 1}}]$
Energy gradient $ = \frac{E}{x} = \frac{{[M{L^2}{T^2}]}}{{[L]}} = [ML{T^{ - 2}}]$
and pressure gradient$ = \frac{P}{x} = \frac{{[M{L^{ - 1}}{T^{ - 2}}]}}{{[L]}} = [M{L^{ - 2}}{T^{ - 2}}]$

Pressure gradient has the same dimension as that of

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