What will be the magnitude of electric field at point $O$ as shown in figure ? Each side of the figure is $I$ and perpendicular to each other.
$\frac{q}{4 \pi \varepsilon_{0}(l)^{2}}$
$\frac{1}{4 \pi \varepsilon_{0}} \frac{q}{(2l^{2})}(2 \sqrt{2}-1)$
$\frac{1}{4 \pi \varepsilon_{0}} \frac{q}{l^{2}}$
$\frac{1}{4 \pi \varepsilon_{0}} \frac{2 {q}}{2l^{2}}(\sqrt{2})$
Two point charges $Q_1, Q_2$ are fixed at $x = 0$ and $x = a$. Assuming that field strength is positive in the direction coinciding with the positive direction of $x$, then, which following option will be correct ?
Give reason : ''Small and light pieces of paper are attracted by comb run through dry hair.''
Three identical point charges, as shown are placed at the vertices of an isosceles right angled triangle. Which of the numbered vectors coincides in direction with the electric field at the mid-point $M$ of the hypotenuse
Electric field at centre $O$ of semicircle of radius $a$ having linear charge density $\lambda$ given is given by
A half ring of radius $R$ has a charge of $\lambda$ per unit length. The electric force on $1\, C$ charged placed at the centre is