Eccentricity of ellipse 25{x^2} + 16{y^2} - 150x - 175 = 0 is

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10-2. Parabola, Ellipse, Hyperbola

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The eccentricity of the ellipse $25{x^2} + 16{y^2} - 150x - 175 = 0$ is

A

$2\over5$

B

$2\over3$

C

$4\over5$

D

$3\over 5$

Solution

(D) $25{(x – 3)^2} + 16{y^2} = 400$

$\frac{{{{(x – 3)}^2}}}{{16}} + \frac{{{y^2}}}{{25}} = 1$

$e = \sqrt {1 – \frac{{16}}{{25}}} = \frac{3}{5}$

Standard 11

Mathematics

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