The eccentricity of the hyperbola $4{x^2} - 9{y^2} = 16$, is
$\frac{8}{3}$
$\frac{5}{4}$
$\frac{{\sqrt {13} }}{3}$
$\frac{4}{3}$
The latus-rectum of the hyperbola $16{x^2} - 9{y^2} = $ $144$, is
The foci of the hyperbola $2{x^2} - 3{y^2} = 5$, is
Let $a$ and $b$ respectively be the semitransverse and semi-conjugate axes of a hyperbola whose eccentricity satisfies the equation $9e^2 - 18e + 5 = 0.$ If $S(5, 0)$ is a focus and $5x = 9$ is the corresponding directrix of this hyperbola, then $a^2 - b^2$ is equal to
Length of latusrectum of curve $xy = 7x + 5y$ is
If the product of the perpendicular distances from any point on the hyperbola $\frac{{{x^2}}}{{{a^2}}}\,\, - \,\,\frac{{{y^2}}}{{{b^2}}}\,\,\, = \,1$ of eccentricity $e =\sqrt 3 \,$ from its asymptotes is equal to $6$, then the length of the transverse axis of the hyperbola is