A plane electromagnetic wave travels in a medium of relative permeability $1.61$ and relative permittivity $6.44$. If magnitude of magnetic intensity is $4.5 \times 10^{-2} \;Am ^{-1}$ at a point, what will be the approximate magnitude of electric field intensity at that point$?$
(Given : permeability of free space $\mu_{0}=4 \pi \times 10^{-7}\;NA ^{-2}$, speed of light in vacuum $c =3 \times 10^{8} \;ms ^{-1}$ )
$16.96\; Vm ^{-1}$
$2.25 \times 10^{-2}\; Vm ^{-1}$
$8.48\; Vm ^{-1}$
$6.75 \times 10^{6} \;Vm ^{-1}$
Suppose that the electric field amplitude of an electromagnetic wave is $E_{0}=120\; N / C$ and that its frequency is $v=50.0\; MHz$.
$(a)$ Determine, $B_{0}, \omega, k,$ and $\lambda .$
$(b)$ Find expressions for $E$ and $B$
A particle of mass $\mathrm{m}$ and charge $\mathrm{q}$ has an initial velocity $\overline{\mathrm{v}}=\mathrm{v}_{0} \hat{\mathrm{j}} .$ If an electric field $\overrightarrow{\mathrm{E}}=\mathrm{E}_{0} \hat{\mathrm{i}}$ and magnetic field $\overrightarrow{\mathrm{B}}=\mathrm{B}_{0} \hat{\mathrm{i}}$ act on the particle, its speed will double after a time:
A radio receiver antenna that is $2 \,m$ long is oriented along the direction of the electromagnetic wave and receives a signal of intensity $5 \times {10^{ - 16}}W/{m^2}$. The maximum instantaneous potential difference across the two ends of the antenna is
The nature of electromagnetic wave is :-
Wavelength of light of frequency $100\;Hz$