2. Electric Potential and Capacitance
medium

मुक्त आकाश में एक बिन्दु पर आवेश $Q$ कूलाम्ब के कारण विभव $Q \times 10^{11}$ वोल्ट है। इस बिन्दु पर विधुतीय क्षेत्र होगा-

A

$4\pi {\varepsilon _0}Q \times 10^{20}\;V/m$

B

$\;12\pi {\varepsilon _0}Q \times {10^{22}}\;V/m$

C

$\;4\pi {\varepsilon _0}Q \times {10^{22}}\;V/m$

D

$\;12\pi {\varepsilon _0}Q \times {10^{20}}\;V/m$

(AIPMT-2008)

Solution

$V =\frac{1}{4 \pi \varepsilon_{0}} \cdot \frac{Q}{r}=Q \cdot 10^{11} \text { volts }$

$\therefore \frac{1}{r} =4 \pi \varepsilon_{0} \cdot 10^{11}$

$E =\frac{\text { potential }}{r}=Q \cdot 10^{11} \times 4 \pi \varepsilon_{0} \cdot 10^{11}$

$\Rightarrow  E=4 \pi \varepsilon_{0} \cdot Q \cdot 10^{22} \mathrm\,{volt/m}$

Standard 12
Physics

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