The electric potential at the surface of an atomic nucleus $(Z = 50)$ of radius $9.0×{10^{ - 13}}\, cm$ is
The electric potential at the surface of an atomic nucleus $(Z = 50)$ of radius $9.0×{10^{ - 13}}\, cm$ is
- A
$80\, volts$
- B
$8 × {10^6}\,volts$
- C
$9\, volts$
- D
$9 × {10^5}\,volts$
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