The electric potential varies in space accord | vedclass

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Question

$\mathrm{E}_{\mathrm{x}}=-\frac{\delta \mathrm{V}}{\delta \mathrm{x}}=-3 \mathrm{\,Vm}^{-1}$

$\mathrm{E}_{\mathrm{y}}=-\frac{\delta \mathrm{V}}{\de

Vedclass · Accepted Answer

$400$

Vedclass · Answer

$\mathrm{E}_{\mathrm{x}}=-\frac{\delta \mathrm{V}}{\delta \mathrm{x}}=-3 \mathrm{\,Vm}^{-1}$

$\mathrm{E}_{\mathrm{y}}=-\frac{\delta \mathrm{V}}{\delta \mathrm{y}}=-4 \mathrm{\,Vm}^{-1}$

$a_{x}=\frac{q E_{1}}{m}=\frac{1 	imes 10^{-6} 	imes 3}{0.1}$

$=-3 	imes 10^{-5} \mathrm{\,ms}^{-2}$

$a_{y}=\frac{q E_{y}}{m}=\frac{1 	imes 10^{-6} 	imes 4}{0.1}$

$=-4 	imes 10^{-5} \mathrm{\,ms}^{-2}$

Time taken to cross the $X$ - axis

Using $s=u t+\frac{1}{2} a t^{2}$

$3.2=\frac{1}{2} 	imes 4 	imes 10^{-5} 	imes t^{2}$

$t=400 \mathrm{\,s}$

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