The energy of a photon of light with waveleng | vedclass

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Question

Energy of photon

$E=\frac{h c}{\lambda}$

$ \Rightarrow \quad 2.5{m{eV}} = \frac{{{m{hc}}}}{{5000 	imes {{10}^{ - 10}}}}$  (as $\l

Vedclass · Accepted Answer

$2.5	imes5000\, eV$

Vedclass · Answer

Energy of photon

$E=\frac{h c}{\lambda}$

$ \Rightarrow \quad 2.5{m{eV}} = \frac{{{m{hc}}}}{{5000 	imes {{10}^{ - 10}}}}$  (as $\lambda  = 5000$ $\mathop {m{A}}\limits^o $)

$\Rightarrow \mathrm{hc}=2.5 	imes 5 	imes 10^{-7} \mathrm{\,eV}$

For $\mathrm{X}-$ ray photon, $\mathrm{c}=$ same, $\mathrm{h}=$ constant

$\Rightarrow \mathrm{E}=\frac{\mathrm{hc}}{\lambda_{\mathrm{x}-\mathrm{ray}}}$

$=\frac{2.5 	imes 5 	imes 10^{-7}}{1 	imes 10^{-10}} \mathrm{eV}$

$=2.5 	imes 5000 \mathrm{\,eV}$

The energy of a photon of light with wavelength $5000\,\mathop A\limits^o $ is approximately $2.5\, eV$. This way the energy of an $X-$ ray photon with wavelength $1\,\mathop A\limits^o $ would be

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