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8.Electromagnetic waves
easy
શૂન્યઅવકાશમાં વિધુતચુંબકીય તરંગની ઊર્જા
A
$\frac{{{E^2}}}{{2{\varepsilon _0}}} + \frac{{{B^2}}}{{2{\mu _0}}}$
B
$\frac{1}{2}{\varepsilon _0}{E^2} + \frac{1}{2}{\mu _0}{B^2}$
C
$\frac{1}{2}{\varepsilon _0}{E^2} + \frac{1}{2}{\mu _0}{B^2}$
D
$\frac{1}{2}{\varepsilon _0}{E^2} + \frac{{{B^2}}}{{2{\mu _0}}}$
(AIIMS-2013)
Solution
$\frac{1}{2}{\varepsilon _0}E_0^2$ is electric energy density. $\frac{{{B^2}}}{{2{\mu _0}}}$ is magnetic energy density. So, total energy $ = \frac{1}{2}{\varepsilon _0}E_0^2 + \frac{{B_0^2}}{{2{\mu _0}}}$
Standard 12
Physics
