Equation of a projectile is y =√{3} x -frac{ gx ^2}{2} angle of projection is

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3-2.Motion in Plane

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The equation of a projectile is $y =\sqrt{3} x -\frac{ gx ^2}{2}$ the angle of projection is

A

$30$

B

$45$

C

$60$

D

એકપણ નહીં.

Solution

$y = x\tan \theta – \frac{{g{x^2}}}{{2{u^2}{{\cos }^2}\theta }}$

$\tan \theta = \sqrt 3 $

$\therefore \,\,\theta = 60^\circ $

Standard 11

Physics

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