Gujarati
10-1.Circle and System of Circles
hard

The equation of pair of tangents to the circle ${x^2} + {y^2} - 2x + 4y + 3 = 0$ from $(6, - 5)$, is

A

$7{x^2} + 23{y^2} + 30xy + 66x + 50y - 73 = 0$

B

$7{x^2} + 23{y^2} + 30xy - 66x - 50y - 73 = 0$

C

$7{x^2} + 23{y^2} - 30xy - 66x - 50y + 73 = 0$

D

None of these

Solution

(a) $S{S_1} = {T^2}$

$ \Rightarrow ({x^2} + {y^2} – 2x + 4y + 3)(36 + 25 – 12x – 20y + 3)$

$ = {(6x – 5y – x – 6 + 2(y – 5) + 3)^2}$

$ \Rightarrow 7{x^2} + 23{y^2} + 30xy + 66x + 50y – 73 = 0$.

Standard 11
Mathematics

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