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10-1.Circle and System of Circles
hard
The equation of pair of tangents to the circle ${x^2} + {y^2} - 2x + 4y + 3 = 0$ from $(6, - 5)$, is
A
$7{x^2} + 23{y^2} + 30xy + 66x + 50y - 73 = 0$
B
$7{x^2} + 23{y^2} + 30xy - 66x - 50y - 73 = 0$
C
$7{x^2} + 23{y^2} - 30xy - 66x - 50y + 73 = 0$
D
None of these
Solution
(a) $S{S_1} = {T^2}$
$ \Rightarrow ({x^2} + {y^2} – 2x + 4y + 3)(36 + 25 – 12x – 20y + 3)$
$ = {(6x – 5y – x – 6 + 2(y – 5) + 3)^2}$
$ \Rightarrow 7{x^2} + 23{y^2} + 30xy + 66x + 50y – 73 = 0$.
Standard 11
Mathematics