The equation of the circle having the lines ${x^2} + 2xy + 3x + 6y = 0$ as its normals and having size just sufficient to contain the circle $x(x - 4) + y(y - 3) = 0$is
The equation of the circle having the lines ${x^2} + 2xy + 3x + 6y = 0$ as its normals and having size just sufficient to contain the circle $x(x - 4) + y(y - 3) = 0$is
- A
${x^2} + {y^2} + 3x - 6y - 40 = 0$
- B
${x^2} + {y^2} + 6x - 3y - 45 = 0$
- C
${x^2} + {y^2} + 8x + 4y - 20 = 0$
- D
${x^2} + {y^2} + 4x + 8y + 20 = 0$
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