The equation of the circle passing through the point $(-2, 4)$ and through the points of intersection of the circle ${x^2} + {y^2} - 2x - 6y + 6 = 0$ and the line $3x + 2y - 5 = 0$, is
The equation of the circle passing through the point $(-2, 4)$ and through the points of intersection of the circle ${x^2} + {y^2} - 2x - 6y + 6 = 0$ and the line $3x + 2y - 5 = 0$, is
- A
${x^2} + {y^2} + 2x - 4y - 4 = 0$
- B
${x^2} + {y^2} + 4x - 2y - 4 = 0$
- C
${x^2} + {y^2} - 3x - 4y = 0$
- D
${x^2} + {y^2} - 4x - 2y = 0$
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