- Home
- Standard 11
- Mathematics
10-2. Parabola, Ellipse, Hyperbola
easy
The equation of the tangents to the hyperbola $3{x^2} - 4{y^2} = 12$ which cuts equal intercepts from the axes, are
A
$y + x = \pm 1$
B
$y - x = \pm 1$
C
$3x + 4y = \pm 1$
D
$3x - 4y = \pm 1$
Solution
(b) The tangent at $(h,k)$ is $\frac{x}{{4/h}} – \frac{y}{{3/k}} = 1$
$\therefore \frac{4}{h} = \frac{3}{k}$
==> $\frac{h}{k} = \frac{4}{3}$…..$(i)$
and $3{h^2} – 4{k^2} = 12$….$(ii)$
As point $(h,k)$ lies on it, using $(i)$ and $(ii),$ we get the tangent as $y – x = \pm 1$.
Standard 11
Mathematics