Gujarati
10-2. Parabola, Ellipse, Hyperbola
easy

The equation of the tangents to the hyperbola $3{x^2} - 4{y^2} = 12$ which cuts equal intercepts from the axes, are

A

$y + x = \pm 1$

B

$y - x = \pm 1$

C

$3x + 4y = \pm 1$

D

$3x - 4y = \pm 1$

Solution

(b) The tangent at $(h,k)$ is $\frac{x}{{4/h}} – \frac{y}{{3/k}} = 1$

$\therefore \frac{4}{h} = \frac{3}{k}$

==> $\frac{h}{k} = \frac{4}{3}$…..$(i)$

and $3{h^2} – 4{k^2} = 12$….$(ii)$

As point $(h,k)$ lies on it, using $(i)$ and $(ii),$ we get the tangent as $y – x = \pm 1$.

Standard 11
Mathematics

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