Equation to sides of a triangle are x - 3y = 0 , 4x + 3y = 5 and 3x + y = 0 . line 3x

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The equation to the sides of a triangle are $x - 3y = 0$, $4x + 3y = 5$ and $3x + y = 0$. The line $3x - 4y = 0$ passes through

The incentre

The centroid

The circumcentre

The orthocentre of the triangle

Solution

(d) Two sides $x – 3y = 0$and $3x + y = 0$of the given triangle are perpendicular to each other. Therefore its orthocentre is the point of intersection of $x – 3y = 0$ and $3x + y = 0$ i.e, $(0, 0)$. Clearly satisfies $3x – 4y = 0$.

Standard 11

Mathematics

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The equation to the sides of a triangle are $x - 3y = 0$, $4x + 3y = 5$ and $3x + y = 0$. The line $3x - 4y = 0$ passes through

Solution

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