The extension of a wire by the application of | vedclass

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Question

(a) $l = \frac{{FL}}{{AY}} \Rightarrow l \propto \frac{1}{{{r^2}}}$ $(F,L$ and $Y$ are constant$)$

$\frac{{{l_2}}}{{{l_1}}} = {\left( {\frac{{{r_1}

Vedclass · Accepted Answer

$12$

Vedclass · Answer

(a) $l = \frac{{FL}}{{AY}} \Rightarrow l \propto \frac{1}{{{r^2}}}$ $(F,L$ and $Y$ are constant$)$

$\frac{{{l_2}}}{{{l_1}}} = {\left( {\frac{{{r_1}}}{{{r_2}}}} ight)^2} = {(2)^2} \Rightarrow {l_2} = 4{l_1} = 4 	imes 3 = 12mm$

The extension of a wire by the application of load is $3$ $mm.$ The extension in a wire of the same material and length but half the radius by the same load is..... $mm$

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