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4-1.Newton's Laws of Motion
easy
The figure shows the position - time $(x-t)$ graph of one-dimensional motion of the body of mass $0.4\; kg$. The magnitude of each impulse is

A
$0.2$
B
$0.4$
C
$0.8$
D
$1.6$
(AIEEE-2010)
Solution
From the graph, it is a straight line so, uniform motion. Because of impulse direction of velocity changes as can be seen from the slope of the graph.
Initial velocity $=\frac{2}{2}=1 m / s$
${ Final velocity } =-\frac{2}{2}=-1 m / s$
$\overrightarrow{{ P }_{i}} =0.4 N – s$
$\overrightarrow{ P_f } =-0.4 N – s$
$\overrightarrow J =\overline{ P }_{f}-\overline{ P }_{i} =-0.4-0.4=-0.8 N – s ( J = impulse )$
$|\overrightarrow J |=0.8 N – s$
Standard 11
Physics