The frequency of vibration of string is given by $\nu = \frac{p}{{2l}}{\left[ {\frac{F}{m}} \right]^{1/2}}$. Here $p$ is number of segments in the string and $l$ is the length. The dimensional formula for $m$ will be
$[{M^0}L{T^{ - 1}}]$
$[M{L^0}{T^{ - 1}}]$
$[M{L^{ - 1}}{T^0}]$
$[{M^0}{L^0}{T^0}]$
List $-I$ | List $-II$ | ||
$A$. | Coefficient of Viscosity | $I$. | $[M L^2T^{–2}]$ |
$B$. | Surface Tension | $II$. | $[M L^2T^{–1}]$ |
$C$. | Angular momentum | $III$. | $[M L^{-1}T^{–1}]$ |
$D$. | Rotational Kinetic energy | $IV$. | $[M L^0T^{–2}]$ |
To find the distance $d$ over which a signal can be seen clearly in foggy conditions, a railways engineer uses dimensional analysis and assumes that the distance depends on the mass density $\rho$ of the fog, intensity (power/area) $S$ of the light from the signal and its frequency $f$. The engineer find that $d$ is proportional to $S ^{1 / n}$. The value of $n$ is:
If velocity $v$, acceleration $A$ and force $F$ are chosen as fundamental quantities, then the dimensional formula of angular momentum in terms of $v,\,A$ and $F$ would be