The general solution of $\tan 3x = 1$ is
The general solution of $\tan 3x = 1$ is
- A
$n\pi + \frac{\pi }{4}$
- B
$\frac{{n\pi }}{3} + \frac{\pi }{{12}}$
- C
$n\pi $
- D
$n\pi \pm \frac{\pi }{4}$
Similar Questions
All the pairs $(x, y)$ that satisfy the inequality ${2^{\sqrt {{{\sin }^2}{\kern 1pt} x - 2\sin {\kern 1pt} x + 5} }}.\frac{1}{{{4^{{{\sin }^2}\,y}}}} \leq 1$ also Satisfy the equation
All the pairs $(x, y)$ that satisfy the inequality ${2^{\sqrt {{{\sin }^2}{\kern 1pt} x - 2\sin {\kern 1pt} x + 5} }}.\frac{1}{{{4^{{{\sin }^2}\,y}}}} \leq 1$ also Satisfy the equation
- [JEE MAIN 2019]
The sum of solutions of the equation $\frac{\cos \mathrm{x}}{1+\sin \mathrm{x}}=|\tan 2 \mathrm{x}|, \mathrm{x} \in\left(-\frac{\pi}{2}, \frac{\pi}{2}\right)-\left\{\frac{\pi}{4},-\frac{\pi}{4}\right\}$ is :
The sum of solutions of the equation $\frac{\cos \mathrm{x}}{1+\sin \mathrm{x}}=|\tan 2 \mathrm{x}|, \mathrm{x} \in\left(-\frac{\pi}{2}, \frac{\pi}{2}\right)-\left\{\frac{\pi}{4},-\frac{\pi}{4}\right\}$ is :
- [JEE MAIN 2021]
One root of the equation $\cos x - x + \frac{1}{2} = 0$ lies in the interval
One root of the equation $\cos x - x + \frac{1}{2} = 0$ lies in the interval
The solution of the equation $\sec \theta - {\rm{cosec}}\theta = \frac{4}{3}$ is
The solution of the equation $\sec \theta - {\rm{cosec}}\theta = \frac{4}{3}$ is
The general solution of $\sin x - \cos x = \sqrt 2 $, for any integer $n$ is
The general solution of $\sin x - \cos x = \sqrt 2 $, for any integer $n$ is