Trigonometrical Equations
normal

$\tan 3x = 1$ का व्यापक हल है

A

$n\pi + \frac{\pi }{4}$

B

$\frac{{n\pi }}{3} + \frac{\pi }{{12}}$

C

$n\pi $

D

$n\pi \pm \frac{\pi }{4}$

Solution

(b) $\tan 3x = 1 \Rightarrow \tan 3x = \tan \frac{\pi }{4}$

$ \Rightarrow 3x = n\pi + \frac{\pi }{4}$$ \Rightarrow $ $x = \frac{{n\pi }}{3} + \frac{\pi }{{12}}$.

Standard 11
Mathematics

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