The general value of theta satisfying the equ | vedclass

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Question

(d) $2{\sin ^2}	heta - 3\sin 	heta - 2 = 0$

$ \Rightarrow $ $(2\sin 	heta + 1)\,\,(\sin 	heta - 2) = 0$

$ \Rightarrow $ $\sin 	heta = - \fr

Vedclass · Accepted Answer

$n\pi + {( - 1)^n}\frac{{7\pi }}{6}$

Vedclass · Answer

(d) $2{\sin ^2}	heta - 3\sin 	heta - 2 = 0$

$ \Rightarrow $ $(2\sin 	heta + 1)\,\,(\sin 	heta - 2) = 0$

$ \Rightarrow $ $\sin 	heta = - \frac{1}{2}$ , $(	herefore \,\sin 	heta  
e 2)$ 

$ \Rightarrow $ $\sin 	heta = \sin \left( {\frac{{ - \pi }}{6}} ight)$

$ \Rightarrow $ $	heta = n\pi + {( - 1)^n}\left( {\frac{{ - \pi }}{6}} ight) $

$\Rightarrow 	heta = n\pi + {( - 1)^{n + 1}}\frac{\pi }{6}$

$ \Rightarrow $ $	heta = n\pi + {( - 1)^n}\frac{{7\pi }}{6}$, $\left\{ \because {\,\,\frac{{ - \pi }}{6}{m{\,\,is \,\,equivalent \,\,to\,\, }}\frac{{7\pi }}{6}} ight\}$.

The general value of $\theta $satisfying the equation $2{\sin ^2}\theta - 3\sin \theta - 2 = 0$ is

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