Gujarati
10-1.Circle and System of Circles
medium

The gradient of the radical axis of the circles ${x^2} + {y^2} - 3x - 4y + 5 = 0$ and $3{x^2} + 3{y^2} - 7x + 8y + 11 = 0$ is

A

$\frac{1}{3}$

B

$ - \frac{1}{{10}}$

C

$ - \frac{1}{2}$

D

$ - \frac{2}{3}$

Solution

(b) Equation of radical axis is $S_1 -S_2 = 0$

${S_1} \equiv {x^2} + {y^2} – 3x – 4y + 5 = 0$

${S_2} \equiv {x^2} + {y^2} – \frac{7}{3}x + \frac{{8y}}{3} + \frac{{11}}{3} = 0$

$\therefore$  Radical axis is $ – 2x – 20y – 4 = 0$

Hence gradient of radical axis $ = – \frac{1}{{10}}$.

Standard 11
Mathematics

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