The equation of circle passing through the points of intersection of circles ${x^2} + {y^2} - 6x + 8 = 0$ and ${x^2} + {y^2} = 6$ and point $(1, 1)$, is

  • [IIT 1980]
  • A

    ${x^2} + {y^2} - 6x + 4 = 0$

  • B

    ${x^2} + {y^2} - 3x + 1 = 0$

  • C

    ${x^2} + {y^2} - 4y + 2 = 0$

  • D

    None of these

Similar Questions

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The number of common tangents to the circles ${x^2} + {y^2} = 4$ and ${x^2} + {y^2} - 6x - 8y = 24$ is

  • [IIT 1998]

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