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13.Nuclei
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The graph which represents the correct variation of logarithm of activity $(log\, A)$ versus time, in figure is
A
$A$
B
$B$
C
$C$
D
$D$
Solution
(d) Activity $A = \lambda \;{N_0}{e^{ – \lambda t}}$
==>${\log _e}A = {\log _e}\lambda \,{N_0} + {\log _e}{e^{ – \lambda t}}$
==> ${\log _e}A = {\log _e}C – \lambda t$ (Take $\lambda N_0 = C$)
==> ${\log _e}A = – \lambda t + {\log _e}C$
This is the equation of a straight line having negative slope ($= -\lambda$) and positive intercept on ${\log _e}A$ axis.
Standard 12
Physics
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