13.Nuclei
hard

Two radioactive substances $X$ and $Y$ originally have $N _{1}$ and $N _{2}$ nuclei respectively. Half life of $X$ is half of the half life of $Y$. After three half lives of $Y$, number of nuclei of both are equal. The ratio $\frac{ N _{1}}{ N _{2}}$ will be equal to

A

$\frac{1}{8}$

B

$\frac{3}{1}$

C

$\frac{8}{1}$

D

$\frac{1}{3}$

(JEE MAIN-2021)

Solution

$T _{ x }= t ; T _{ y }=2 t$

$3 T _{ y }=6 t$

$N _{1}^{\prime}= N _{2}^{\prime}$

$N _{1} e ^{-\lambda_{1} 6 t }= N _{2} e ^{-\lambda_{2} 6 t }$

$\frac{ N _{1}}{ N _{2}}= e ^{\left(\lambda_{1}-\lambda_{2}\right) 6 t }= e ^{\ln 2\left(\frac{1}{t}-\frac{1}{2 t }\right) \times 6 t }= e ^{(1 n 2) \times 3}= e ^{ ln 8}=8$

$\frac{ N _{1}}{ N _{2}}=\frac{8}{1}$

Standard 12
Physics

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