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13.Nuclei
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Two radioactive substances $X$ and $Y$ originally have $N _{1}$ and $N _{2}$ nuclei respectively. Half life of $X$ is half of the half life of $Y$. After three half lives of $Y$, number of nuclei of both are equal. The ratio $\frac{ N _{1}}{ N _{2}}$ will be equal to
A
$\frac{1}{8}$
B
$\frac{3}{1}$
C
$\frac{8}{1}$
D
$\frac{1}{3}$
(JEE MAIN-2021)
Solution
$T _{ x }= t ; T _{ y }=2 t$
$3 T _{ y }=6 t$
$N _{1}^{\prime}= N _{2}^{\prime}$
$N _{1} e ^{-\lambda_{1} 6 t }= N _{2} e ^{-\lambda_{2} 6 t }$
$\frac{ N _{1}}{ N _{2}}= e ^{\left(\lambda_{1}-\lambda_{2}\right) 6 t }= e ^{\ln 2\left(\frac{1}{t}-\frac{1}{2 t }\right) \times 6 t }= e ^{(1 n 2) \times 3}= e ^{ ln 8}=8$
$\frac{ N _{1}}{ N _{2}}=\frac{8}{1}$
Standard 12
Physics
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