Gujarati
13.Nuclei
medium

एक रेडियोसक्रिय पदार्थ की अर्द्धआयु $3.6$ दिन है $36$ दिन बाद इस पदार्थ के $20\, mg$ मात्रा में से कितना ............ $mg$ शेष बचेगा

A

$0.0019$

B

$1.019$

C

$1.109$

D

$0.019$

Solution

$M = {M_0}{\left( {\frac{1}{2}} \right)^{\frac{t}{{{T_{1/2}}}}}}$

$ = 20 \times {\left( {\frac{1}{2}} \right)^{\frac{{3.6}}{{3.6}}}}$

$ = 20 \times {\left( {\frac{1}{2}} \right)^{10}} = 0.019\,mg$

Standard 12
Physics

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