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4-1.Complex numbers
easy
The imaginary part of $\frac{{{{(1 + i)}^2}}}{{(2 - i)}}$is
A
$\frac{1}{5}$
B
$\frac{3}{5}$
C
$\frac{4}{5}$
D
None of these
Solution
(c) We have $\frac{{{{(1 + i)}^2}}}{{2 – i}} = \frac{{(2i)(2 + i)}}{{(2 – i)(2 + i)}}$$ = – \frac{2}{5} + i\frac{4}{5}$.
Thus $Im\ (z) = \frac{4}{5}$.
Standard 11
Mathematics