11.Thermodynamics
normal

The internal energy change in a system that has absorbed $2\,\, kcal$ of heat and done $500\, J$ of work is ........... $\mathrm{J}$

A

$7900$

B

$8200$

C

$5600$

D

$6400$

Solution

Heat energy given $d Q=d U+d W$ where $d U$ is the change in internal energy and $d W$ is the work done.

Given $d Q=2 \mathrm{kcal}=2000 \times 4.2 \mathrm{J}$ and $d W=500 \mathrm{\,J}$

$\therefore \quad 2000 \times 4.2=d U+500 \Rightarrow d U=7900 \mathrm{\,J}$

Standard 11
Physics

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