The length of a wire is $1.0\, m$ and the area of cross-section is $1.0 \times {10^{ - 2}}\,c{m^2}$. If the work done for increase in length by $0.2\, cm$ is $0.4\, joule$, then Young's modulus of the material of the wire is
The length of a wire is $1.0\, m$ and the area of cross-section is $1.0 \times {10^{ - 2}}\,c{m^2}$. If the work done for increase in length by $0.2\, cm$ is $0.4\, joule$, then Young's modulus of the material of the wire is
- A
$2.0 \times {10^{10}}\,N/{m^2}$
- B
$4 \times {10^{10}}\,N/{m^2}$
- C
$2.0 \times {10^{11}}\,N/{m^2}$
- D
$2 \times {10^{10}}\,N/{m^2}$
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