10-1.Circle and System of Circles
hard

The locus of centre of a circle passing through $(a, b)$ and cuts orthogonally to circle ${x^2} + {y^2} = {p^2}$, is

A

$2ax + 2by - ({a^2} + {b^2} + {p^2}) = 0$

B

$2ax + 2by - ({a^2} - {b^2} + {p^2}) = 0$

C

${x^2} + {y^2} - 3ax - 4by + ({a^2} + {b^2} - {p^2}) = 0$

D

${x^2} + {y^2} - 2ax - 3by + ({a^2} - {b^2} - {p^2}) = 0$

(AIEEE-2005) (IIT-1988)

Solution

(a) Let equation of circle be ${x^2} + {y^2} + 2gx + 2fy + c = 0$ with ${x^2} + {y^2} = {p^2}$ cutting orthogonally,

we get $0 + 0 = + c – {p^2}$

or $c = {p^2}$ and passes through $(a, b)$,

we get ${a^2} + {b^2} + 2ga + 2fb + {p^2} = 0$ or

$2ax + 2by – ({a^2} + {b^2} + {p^2}) = 0$

Required locus as centre $( – g,\; – f)$ is changed to $(x, y)$.

Standard 11
Mathematics

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