The locus of point of intersection of two perpendicular tangent of the ellipse $\frac{{{x^2}}}{{{9}}} + \frac{{{y^2}}}{{{4}}} = 1$ is :-
The locus of point of intersection of two perpendicular tangent of the ellipse $\frac{{{x^2}}}{{{9}}} + \frac{{{y^2}}}{{{4}}} = 1$ is :-
- A
$x^2 + y^2 = 4$
- B
$x^2 + y^2 = 9$
- C
$x^2 + y^2 = 13$
- D
$x^2 + y^2 = 5$
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- [AIEEE 2012]