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Mathematical Reasoning
normal
The logically equivalent of $p \Leftrightarrow q$ is :-
A
$(p \wedge q) \vee (p \wedge q)$
B
$(p \Rightarrow q) \wedge (q \Rightarrow p)$
C
$(p \wedge q) \vee (q \Rightarrow p)$
D
$(p \wedge q) \Rightarrow (q \vee p)$
Solution
$(p \Rightarrow q) \wedge (q \Rightarrow p)$ means $p \Leftrightarrow q$
Standard 11
Mathematics