Maximum elongation of a steel wire of 1 mathrm{~m} length if elastic limit of steel and its Young&#3

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8.Mechanical Properties of Solids

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The maximum elongation of a steel wire of $1 \mathrm{~m}$ length if the elastic limit of steel and its Young's modulus, respectively, are $8 \times 10^8 \mathrm{~N} \mathrm{~m}^{-2}$ and $2 \times 10^{11} \mathrm{~N} \mathrm{~m}^{-2}$, is:

$0.4 \mathrm{~mm}$

$40 \mathrm{~mm}$

$8 \mathrm{~mm}$

$4 \mathrm{~mm}$

(NEET-2024)

Solution

In the case for maximum elongation,

Stress $=$ Elastic limit

$\delta_{\text {max }}=\frac{\sigma_{\text {elastlc }} \times L}{\text { Young's modulus }}=\frac{8 \times 10^8 \times 1}{2 \times 10^{11}} =4 \times 10^{-3}$

$=4 \mathrm{~mm}$

i.e. maximum elongation is $4 \mathrm{~mm}$

Standard 11

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(JEE MAIN-2022)

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The maximum elongation of a steel wire of $1 \mathrm{~m}$ length if the elastic limit of steel and its Young's modulus, respectively, are $8 \times 10^8 \mathrm{~N} \mathrm{~m}^{-2}$ and $2 \times 10^{11} \mathrm{~N} \mathrm{~m}^{-2}$, is:

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