3-2.Motion in Plane
easy

A cricket ball is thrown by a player at a speed of $20\,m / s$ in a direction $30^{\circ}$ above the horizontal. The maximum height attained by the ball during its motion is $........\,m$ $\left( g =10\,m / s ^2\right)$

A

$5$

B

$10$

C

$20$

D

$25$

(NEET-2022)

Solution

$H =\frac{ u ^2 \sin ^2 \theta}{2 g }=\frac{(20)^2 \sin ^2 30^{\circ}}{2(10)}$

$=5$

Standard 11
Physics

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