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3-2.Motion in Plane
easy
A cricket ball is thrown by a player at a speed of $20\,m / s$ in a direction $30^{\circ}$ above the horizontal. The maximum height attained by the ball during its motion is $........\,m$ $\left( g =10\,m / s ^2\right)$
A
$5$
B
$10$
C
$20$
D
$25$
(NEET-2022)
Solution
$H =\frac{ u ^2 \sin ^2 \theta}{2 g }=\frac{(20)^2 \sin ^2 30^{\circ}}{2(10)}$
$=5$
Standard 11
Physics
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