The mean lives of a radioactive sample are 30 | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

${\lambda _{(\alpha  + \beta )}} = {\lambda _\alpha } + {\lambda _\beta }$

$ \Rightarrow \frac{1}{{{T_{\frac{1}{2}(\alpha  - \beta )}}}}

Vedclass · Accepted Answer

$40$

Vedclass · Answer

${\lambda _{(\alpha  + \beta )}} = {\lambda _\alpha } + {\lambda _\beta }$

$ \Rightarrow \frac{1}{{{T_{\frac{1}{2}(\alpha  - \beta )}}}} = \frac{1}{{{T_{\frac{1}{2}(\alpha )}}}} + \frac{1}{{{T_{\frac{1}{2}\left( \beta  ight)}}}}$

$\Rightarrow \frac{1}{T_{\frac{1}{2}(x+\beta)}}=\frac{1}{30}+\frac{1}{60}=\frac{1}{20}$

$	herefore {{m{T}}_{\frac{1}{2}(\alpha  + \beta )}} = 20$ years.

$	herefore $ One-fourth of sample will remain after $2$ half life $=40$ years.

The mean lives of a radioactive sample are $30$ years and $60$ years for $\alpha$-emission and $\beta $ -emission respectively. If the sample decays both by $\alpha$- emission and $\beta $-emission simultaneously, the time after which, only one-fourth of the sample remain is :- ........... $years$

Similar Questions

In a radioactive decay process , the negatively charged emitted $\beta -$ particles are

The activity of a radioactive sample

In a radioactive decay chain reaction, ${ }_{90}^{230} Th$ nucleus decays into ${ }_{84}^{214} Po$ nucleus. The ratio of the number of $\alpha$ to number of $\beta^{-}$particles emitted in this process is. . . . .

Two species of radioactive atoms are mixed in equal number. The disintegration constant of the first species is $\lambda$ and of the second is $\lambda / 3$. After a long time the mixture will behave as a species with mean life of approximately

If half life of an element is $69.3$ hours then how much of its percent will decay in $10^{\text {th }}$ to $11^{\text {th }}$ hours. Initial activity $=50\, \mu Ci$