Gujarati
Hindi
13.Nuclei
medium

The mean lives of a radioactive sample are $30$ years and $60$ years for $\alpha$-emission and $\beta $ -emission respectively. If the sample decays both by $\alpha$- emission and $\beta $-emission simultaneously, the time after which, only one-fourth of the sample remain is :- ........... $years$

A

$10$ 

B

$20$ 

C

$40$ 

D

$45$ 

Solution

${\lambda _{(\alpha  + \beta )}} = {\lambda _\alpha } + {\lambda _\beta }$

$ \Rightarrow \frac{1}{{{T_{\frac{1}{2}(\alpha  – \beta )}}}} = \frac{1}{{{T_{\frac{1}{2}(\alpha )}}}} + \frac{1}{{{T_{\frac{1}{2}\left( \beta  \right)}}}}$

$\Rightarrow \frac{1}{T_{\frac{1}{2}(x+\beta)}}=\frac{1}{30}+\frac{1}{60}=\frac{1}{20}$

$\therefore {{\rm{T}}_{\frac{1}{2}(\alpha  + \beta )}} = 20$ years.

$\therefore $ One-fourth of sample will remain after $2$ half life $=40$ years.

Standard 12
Physics

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