In a RA element the fraction of initiated amo | vedclass

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Question

Given,

a Radioactive element

mean life time $=\frac{1}{\lambda}$

Let $A _0=$ initial no. of nuclie

afiuhter any time $= t$, no of nuclie l

Vedclass · Accepted Answer

$\frac{1}{e}$

Vedclass · Answer

Given,

a Radioactive element

mean life time $=\frac{1}{\lambda}$

Let $A _0=$ initial no. of nuclie

afiuhter any time $= t$, no of nuclie left $= A _{ t }$

$A _{ t }= A _0 e ^{-\lambda t }, \lambda=$ decay constant

$A _{ t }= A _0 e ^{-\lambda 	imes \frac{1}{\lambda} \quad 	herefore\quad t _{	ext {mean }}}=\frac{1}{\lambda}$

$A _{ t }= A _0 e ^{-1}$

$A _{ t }=\frac{ A _0}{ e }$

$\left(\frac{A_*}{A_0}ight)=\frac{1}{e}=$ fraction of ammount left

In a $RA$ element the fraction of initiated amount remaining after its mean life time is

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