The mean of the series $a,a + nd,\,\,a + 2nd$ is
$a + (n - 1)\,d$
$a + nd$
$a + (n + 1)\,d$
None of these
(b) Mean $ = \frac{{a + (a + nd) + (a + 2nd)}}{3}$
$ = \frac{{3a + 3nd}}{3} = a + nd$.
The sum of all the elements of the set $\{\alpha \in\{1,2, \ldots, 100\}: \operatorname{HCF}(\alpha, 24)=1\}$ is
If $\tan \left(\frac{\pi}{9}\right), x, \tan \left(\frac{7 \pi}{18}\right)$ are in arithmetic progression and $\tan \left(\frac{\pi}{9}\right), y, \tan \left(\frac{5 \pi}{18}\right)$ are also in arithmetic progression, then $|x-2 y|$ is equal to:
The sum of numbers from $250$ to $1000$ which are divisible by $3$ is
The sum of the numbers between $100$ and $1000$, which is divisible by $9$ will be
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