The mean of the series $a,a + nd,\,\,a + 2nd$ is
$a + (n - 1)\,d$
$a + nd$
$a + (n + 1)\,d$
None of these
(b) Mean $ = \frac{{a + (a + nd) + (a + 2nd)}}{3}$
$ = \frac{{3a + 3nd}}{3} = a + nd$.
The ${n^{th}}$ term of an $A.P.$ is $3n – 1$.Choose from the following the sum of its first five terms
The sixth term of an $A.P.$ is equal to $2$, the value of the common difference of the $A.P.$ which makes the product ${a_1}{a_4}{a_5}$ least is given by
If the sum of two extreme numbers of an $A.P.$ with four terms is $8$ and product of remaining two middle term is $15$, then greatest number of the series will be
Find the $9^{\text {th }}$ term in the following sequence whose $n^{\text {th }}$ term is $a_{n}=(-1)^{n-1} n^{3}$
Confusing about what to choose? Our team will schedule a demo shortly.
