The normal at the point $(3, 4)$ on a circle cuts the circle at the point $(-1, -2)$. Then the equation of the circle is
The normal at the point $(3, 4)$ on a circle cuts the circle at the point $(-1, -2)$. Then the equation of the circle is
- A
${x^2} + {y^2} + 2x - 2y - 13 = 0$
- B
${x^2} + {y^2} - 2x - 2y - 11 = 0$
- C
${x^2} + {y^2} - 2x + 2y + 12 = 0$
- D
${x^2} + {y^2} - 2x - 2y + 14 = 0$
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