At which point on $y$-axis the line $x = 0$ is a tangent to circle ${x^2} + {y^2} - 2x - 6y + 9 = 0$

  • A

    $(0, 1)$

  • B

    $(0, 2)$

  • C

    $(0, 3)$

  • D

    $(0, 4)$

Similar Questions

Match the statements in Column $I$ with the properties Column $II$ and indicate your answer by darkening the appropriate bubbles in the $4 \times 4$ matrix given in the $ORS$.

Column $I$ Column $II$
$(A)$ Two intersecting circles $(p)$ have a common tangent
$(B)$ Two mutually external circles $(q)$ have a common normal
$(C)$ two circles, one strictly inside the other $(r)$ do not have a common tangent
$(D)$ two branches of a hyperbola $(s)$ do not have a common normal

  • [IIT 2007]

In the figure, $A B C D$ is a unit square. A circle is drawn with centre $O$ on the extended line $C D$ and passing through $A$. If the diagonal $A C$ is tangent to the circle, then the area of the shaded region is

  • [KVPY 2017]

Tangent to the circle $x^2 + y^2$ = $5$ at the point $(1, -2)$ also touches the circle $x^2 + y^2 -8x + 6y + 20$ = $0$ . Then its point of contact is 

The normal at the point $(3, 4)$ on a circle cuts the circle at the point $(-1, -2)$. Then the equation of the circle is

Given the circles ${x^2} + {y^2} - 4x - 5 = 0$and ${x^2} + {y^2} + 6x - 2y + 6 = 0$. Let $P$ be a point $(\alpha ,\beta )$such that the tangents from P to both the circles are equal, then