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10-1.Circle and System of Circles
medium
At which point on $y$-axis the line $x = 0$ is a tangent to circle ${x^2} + {y^2} - 2x - 6y + 9 = 0$
A
$(0, 1)$
B
$(0, 2)$
C
$(0, 3)$
D
$(0, 4)$
Solution
(c) For $x = 0$, we get ${y^2} – 6y + 9 = 0$ or ${(y – 3)^2} = 0$
$i.e$., point of contact is $(0, 3).$
Standard 11
Mathematics