The nuclear radius is given by R=r_0 A^{1 / 3 | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(c)

Given, nuclear radius is

$R=r_0 A^{\frac{1}{3}}$

Here, atomic mass number of nucleus $=A$

$	herefore$ Nuclear density $d$ is given by

Vedclass · Accepted Answer

same as that of $Sn ^{119}$

Vedclass · Answer

(c)

Given, nuclear radius is

$R=r_0 A^{\frac{1}{3}}$

Here, atomic mass number of nucleus $=A$

$	herefore$ Nuclear density $d$ is given by

$d=\frac{	ext { Mass number }}{	ext { Volume }}$

$\Rightarrow \quad d=\frac{A}{\frac{1}{3} \pi R^3}=\frac{4}{3} \pi\left(r_0 A^{\left.\frac{1}{3}ight)^3}ight.$

$\Rightarrow \quad d=\frac{A}{\frac{1}{3} \pi r_0^3 \cdot A}=\frac{3}{4 \pi r_0^3}$

As $r_0=$ a constant, so nuclear density is a constant quantity.

$	herefore$ Nuclear mass density of $U^{238}$ is same as that of $Sn ^{119}$.

The nuclear radius is given by $R=r_0 A^{1 / 3}$, where $r_0$ is constant and $A$ is the atomic mass number. Then, the nuclear mass density of $U^{238}$ is

Similar Questions

$1 a.m.u.$ is equivalent to

Assume that protons and neutrons have equal masses. Mass of a nucleon is $1.6 \times 10^{-27}\,kg$ and radius of nucleus is $1.5 \times 10^{-15} A ^{1 / 3}\,m$. The approximate ratio of the nuclear density and water density is $n \times 10^{13}$. The value of $n$ is $.................$

What kind of a force does neutron-neutron ?

The ratio of radii of nuclei $_{13}A{l^{27}}$ and $_{52}{X^A}$ is $3 : 5$. The number of neutrons in the nuclei of $X$ will be

The nuclei of which one of the following pairs of nuclei are isotones