The ratio of radii of nuclei _{13}A{l^{27}} a | vedclass

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Question

(b) $r \propto {A^{1/3}}$ ==> $\frac{{{r_1}}}{{{r_2}}} = {\left( {\frac{{{A_1}}}{{{A_2}}}} \right)^{1/3}}$

==> $\frac{3}{5} = {\left( {\frac{

Vedclass · Accepted Answer

$73$

Vedclass · Answer

(b) $r \propto {A^{1/3}}$ ==> $\frac{{{r_1}}}{{{r_2}}} = {\left( {\frac{{{A_1}}}{{{A_2}}}} \right)^{1/3}}$

==> $\frac{3}{5} = {\left( {\frac{{27}}{A}} \right)^{1/3}}$

==> $\frac{{27}}{{125}} = \frac{{27}}{A}$

==> $A = 125$ 

Number of nuclei in atom $X   = A - 52 = 125 - 52 = 73.$

The ratio of radii of nuclei $_{13}A{l^{27}}$ and $_{52}{X^A}$ is $3 : 5$. The number of neutrons in the nuclei of $X$ will be

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